Question

Two congruent "door-stop" trapezoids are placed edge-to-edge with measurements and markings as shown. Find the length of

Answer 1

find the length of

Answer 2

EB^2=BF^2-EF^2=25^2-20^2=625-400=225
EB=sqrt(225)=15
EB=AB=BC(given)
so AC=AB+AB=EC+EC=15+15=30

Answer 3

\[BF ^{2} = BE ^{2} + EF ^{2}\]
\[( 25cm )^{2} = BE ^{2} + ( 20cm )^{2}\]
BE = 15cm

since BE = AB = BC, and AC = AB + BC According to the figure
AC = 2*BE
AC= 2*15cm
AC = 30 cm