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Mathematics 16 Online
OpenStudy (anonymous):

derivative of f(z)=sqrt(ze^-z)

OpenStudy (anonymous):

\[f(z)=\sqrt{ze^{-z}}\]?

OpenStudy (anonymous):

\[f'(z)=\frac{1}{2\sqrt{ze^{-z}}}\times \frac{d}{dz}ze^{-z}\] and the second part you get by the product rule

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