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Find the inverse function..
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write the function without the function notation\[y=\frac{2x-3}{x+5}\]exchange the positions of the domain and range variables\[x=\frac{2y-3}{y+5}\]solve for y\[xy+5x=2y-3\]\[5x+3=2y-xy\]\[5x+3=y(2-x)\]\[y=f ^{-1}(x)=\frac{5x+3}{2-x}\]
The domain of f is the same as the range of f-inverse\[(-\infty,5) \cup(5, \infty)\]
Thank you MANDOLINO!!!!
ur welcome :}) FYI: Here is the function and its inverse graphed; note they are symmetric about the line y=x; this is true of any function and its inverse
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O wow thank you so much!
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