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Evaluate the limit as t-->infty of (3t^5-8)/(t^10-3t^1-7)
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can you use l'hospitals
Sorry, its (3t^5-8)/square root of(t^10-3t^1-7)
And I didn't learn that rule yet
can we multiply the top and bottom by sqrt(t^10-3t^1-7)
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now, here is what we can do, lets write everything under a big sqrt, then divide all the terms by t^10
Is this what you mean?
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