Question

[find limit]

limit as x approaches infinity (√(9x^2+x)-3x)

Answer 1

1/6

Answer 2

method is to multiply by
\[\frac{\sqrt{9x^2+3}+3x}{\sqrt{9x^2+3}+3x}\] unless there is a snap way i don't know
zarkon?

Answer 3

that is the way I did it

Answer 4

is it multiplying by the conjugate or how did you get that?