Question

y(y-3)=4, solve for y

Answer 1

quad form. y^2-3y-4=0

Answer 2

okay thanks

Answer 3

y2-3y-4=0
y2-4y+y-4=0
y(y-4)+(y-4)=0
(y+1)(y-4)=0

Answer 4

y^2-3y-4=0; then factor, we get (y-4)(y+1); values of y= 4, -1