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Mathematics 12 Online
OpenStudy (anonymous):

A proton is moving with velocity of 10000 m/s parallel to the magnetic field intensity of 5 tesla. Find the force on the proton.

OpenStudy (anonymous):

zero

OpenStudy (anonymous):

How?

OpenStudy (anonymous):

force on a point charge moving in a magnetic field with a velocity v is \[F=q(vXB)\] x denotes cross product between velocity and field vectors. here in the problem since they are parallel cross product is zero

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