Question

let f(x)=e^-1 and g(x)-1n(x+2). Find all points of intersection for the graphs of f and g.

Answer 1

need a little clarification here.
is it
\[f(x)=e^{-1}\] ? that is a constant. and
\[g(x)=\ln(x+2)\]?

\[g(x)=-\ln(x+2)\]?

Answer 2

sorry..typo there... it she bef(x)=e^x-1

Answer 3

shd

Answer 4

g(x)=ln(x+2)

Answer 5

\[f(x)=e^{x-1}\] is that it?

Answer 6

\[f(x)=e ^{x}-1\]

Answer 7

http://www.wolframalpha.com/input/?i=solve+e^x-1%3Dln%28x%2B2%29&asynchronous=false&equal=Submit

Answer 8

retype question: Let \[f(x)= e ^{x}-1\] and \[g(x)=1n(x=2)\]. Find all points of intersection for the graphs of f and g.