Question

need help on attachment

Answer 1

First differentiate the whole equation with respect to t
Next plug dy/dt = 6 x=1/5 and y = 1/5 then find dx/xt

Answer 2

\[2x^3+3y^3=xy\]
\[6x^2x'+9y^2y'=x'y+y'x\] isolate x'
\[x'(6x^2-y)=y'x-9y^2y'\]
\[x'=(y'x-9y^2y')/(6x^2-y)\]
plug in the appropriate values x=1/5, y=1/5, y'=6

Answer 3

so is it increasing or decreasing

Answer 4

I got 4.651 I don't think that right