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OpenStudy (anonymous):
make a table of values for each equation. then graph y=/x+2/ pleaseeeee help me
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OpenStudy (anonymous):
Are those supposed to be absolute value signs?
OpenStudy (anonymous):
yesss
OpenStudy (anonymous):
y=|x+2|?
OpenStudy (anonymous):
What do you have for your table of values so far?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
to graph it all you have to do is shift the parent graph y=|x| 2 units to the left.. so y= 0 being on the origin it is now on x=2
OpenStudy (anonymous):
please help y=/2x-1/+4
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