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Mathematics 15 Online
OpenStudy (anonymous):

5+^2-23t-10

OpenStudy (anonymous):

is that \[5t^2-23t-10\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

if so, rewrite -23 as -25t+2t\[=5t^2-25t+2t-10\]factor by grouping\[=5t(t-5)+2(t-5)\]factor out binomial\[=(t-5)(5t+2)\]

OpenStudy (anonymous):

the method is to rewrite the middle terms using factor of 5*(-10)=-50 that sum to -23; those are -25 and +2

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