The formula S = 16t^2 + v0t + s0 tells the height at time t of a projectile fired vertically from height s0 with initial velocity v0.
Suppose a projectile is fired vertically from ground level at an initial speed of 448 ft per second.
When will the projectile be higher than 3072 ft?

Question

The formula S = 16t^2 + v0t + s0 tells the height at time t of a projectile fired vertically from height s0 with initial velocity v0.
Suppose a projectile is fired vertically from ground level at an initial speed of 448 ft per second. 
When will the projectile be higher than 3072 ft?

anonymous · Answer

in this case 
$$v_0=448, h_0=0$$ and your equation is 
$$S=-16t^2+448t$$ 
your job now is to solve 
$$-16t^2+448t>3072$$ or 
$$16t^2-448t+3072<0$$

anonymous · Answer

thank you so much I upgrade you to Godly lol

anonymous · Answer

ok what is the next step i keep ending up with a long decimal

anonymous · Answer

ok here finally