Question

find the derivative of:
arcsin(6x)

Answer 1

http://www.analyzemath.com/calculus/Differentiation/inverse_trigonometric.html

Answer 2

im pretty sure its were you left it :)

Answer 3

Let y = arcsin(6x). Then x = 1/6 . sin(y)

Now, dx/dy = 1/6 . cos y
= 1/6 sqrt(1 - sin^2 y)
= 1/6 sqrt(1 - (6x)^2)

Thus

dy/dx = 6/sqrt( 1 - (6x)^2 )

Answer 4

sin-1(6x) = y

6x =sin(y)

6 =cos(y) y'

6/cos(y) = y'