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\[(\log_{b}ab) ^{-1}+( \log_{a}ab) ^{-1}\]=?
\[= ( \log_{b} (b) + \log_{b}(a))^{-1} + (\log_{a} (a) + \log_{a} (b) )^{-1}\]
\[= \frac{1}{1+ \log_{b}(a)} + \frac{1}{1+\log_{a}(b)}\]
There is nothing else you can do to simplify it. In fact, the starting expression is the simplest of all.
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