Question

solve each system of equations.
2y^2-3xy+6y+2x+4=0
2x-3y+4=0

Answer 1

2x-3y+4=0, 2x=3y-4, x=(3/2)y-2 now substitute for in the 2nd degree equation.
This gives you the following:
\[2y ^{2}-(9/2)y ^{2}+6y+6y+3y-4+4=0\]\[(-5/2)y ^{2}+15y=0\] Multiply both sides by a -2 getting:\[5y ^{2}-30y=0\] Factor getting:
5y(y-6)=0 Solve for y getting:
y=0
y=6

Answer 2

Solving for x:
2x-0+4=0
2x=-4
x=-2
Other value
2x-18+4=0
2x=14
x=7

Answer 3

Did you follow with understanding?

Answer 4

yes!! thank you so much!!

Answer 5

Good luck with your studies.