Question

factor 20c^2+11c-3

Answer 1

\[Ac^2+Bc+C\]
we need to find two factors of A*C that have product A*C and have sum B
A=20
B=11
C=-3
A*C=20(-3)=10(-6)=5(-12)=15(-4)
B=11=15-4 =====> Bc=15c-4c
so we have
20c^2+15c-4c-3
we factor by grouping now
the first two terms have gcf=5c
the second two terms have -1 in common
so we can write
5c(4c+3)-1(4c+3)
we have terms now and they both have the factor (4c+3) in common
so we can write
(4c+3)(5c-1)

Answer 2

thanks