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factor .note the middle term has already been split u^2+2u+8u+16
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u=13 0r -23
u^(2)+2u+8u+16 Since 2u and 8u are like terms, add 8u to 2u to get 10u. u^(2)+10u+16 Since the coefficient of u^(2) is 1, the coefficients of the left-hand term in each factor must be 1. (u )(u ) For a polynomial of the form ax^(2)+bx+c, find two factors of c (16) that add up to b (10). a=1, b=10, c=16 In this problem 8*2=16 and 8+2=10, so insert 8 as the right hand term of one factor and 2 as the right-hand term of the other factor. (u+8)(u+2)
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