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can someone help me on the attachment and not go to wolfframealpha to show me how to work it
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\[f(x)=(x^2-2)/\sqrt{x^2-1}\] quotient rule would be a pain here so let's rewrite this as a product of two functions: \[f(x)=(x^2-2)/\sqrt{x^2-1}=(x^2-2)(x^2-1)^(-1/2)\] that's (x^2-1)^(-1/2) on the right there... product rule (fg)'=f'g+g'f
ok
\[f'(x)=2x(x^2-1)^(-1/2)-(x^2-2)(1/2)(x^2-1)^(-3/2)(2x)\] \[=2x/\sqrt{x^2-1}-(x^3-2x)/\sqrt{(x^2-1)^3}\] simplify
but that not one of the answer choices here a list
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the first answer choice is on the first attachment where its show the problem
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