Question

solve each system of equations.
5/x^2-2/y^2+3=0
3/x^2+1/y^2=7

Answer 1

you should write the equations in a clear form next time. add some parentheses.

Answer 2

i think you mean
\[(5/x^2)-(2/y^2)+3=0 \]
\[(3/x^2)+(1/y^2)=7\]

Answer 3

multiply 2nd equation by 2. then add 1st and 2nd eqns.

Answer 4

you get (11/x^2)=11, so x=1.

Answer 5

if x=1, considering 2nd equation, (3/1^2)+(1/y^2)=7, 1/y^2=4, y=1/2.

Answer 6

thanks