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factor by grouping 3c^2+1c-24
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If all you're looking for is an answer: (c+3)(3c-8)
ac=-72, then rewrite c as 9c-8c 3c^2-8c+9c-24=c(3c-8)+3(3c-8)=(3c-8)(c+3)
by rewriteing the middle terms using factors of 3*(-24)=-72 we can factor by grouping
this process allows you to "reverse" the steps you would get from a FOIL if you started with (3c-8)(c+3)
FOIL: (3c-8)(c+3) = 3c^2+9c -8c -24 F 0 I L
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