Question

Give the slope of the line through the points (0,3) and (5,0)

Answer 1

Use the formula.

Answer 2

\[slope = \frac{y_2-y_1}{x_2-x_1}\]

Answer 3

Do you need help applying this formula?

Answer 4

@CHAISE: grr, yes >__<

Answer 5

Okay - The slope formula is what Saifoo said it was. When I look at the problems I point the points directly on top of eachother, take them away and then divide y by x.
Your points are (in (x,y) format:
(0,3)
(5,0)

If we take the y value from the y value directly below it we get (3-0) 3. If we take away the x value with the x value directly below it we get (0-5) -5.

Now we must divide the y value by the x value (as this is rise / run which is the definition of a slope)
3/-5

The slope is -3/5.

Answer 6

mhmm, i see...well, kind of. lol >_< grr
thanks :D

Answer 7

@chasie-so id divide 3/5 then get my answer ?

Answer 8

you missed the negative sign.

Answer 9

ok , but other then that i divide to get the last answer ..? rite?

Answer 10

Correct.

Answer 11

i got it ^____^
THANK U CHAISE & SAIFOO!

Answer 12

uw.

Answer 13

If you would like a further, in-depth explanation of a slope I would be happy to explain it to you.

Answer 14

@chaise- thank you very much :) i got other problems ill post up not sure if it's having to do with slope, but i very much understood everything on how you explained it to me for this problem.^__^
ALOHA

Answer 15

lol, try to learn that method, so that u can solve them later as well

Answer 16

They really arn't that hard - and I find them enjoyable cause they're so logical. I love linear equations and I always try to thoroughly explain them when people have troubles with them.

Answer 17

LOL, ill try as much as i can. brr, it's just i learn it, then forget it.lol

Answer 18

haha. SHORT TERM MEM LOSS. jk jk

Answer 19

@chaise-thats cool that you love the subject, grr , i hate math !

Answer 20

it's so easy.

Answer 21

@saifoo- ahah, HEY ! NO TEASEING . mean-o ):

Answer 22

haha^

Answer 23

its easy for you guys because i dont get the help i need, good thing i found this website...lol