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Evaluate 9 - x^2 is greater than or equal to 0. The question I have about this is that under what conditions is the inequality sign "flipped"? Does it occur here, when you square both sides of the inequality?
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the sign is flipped if and only if you multiply the other side by a negative number
Are you sure it doesn't count if you square both sides?
Because the answer I got down for this is [-3,3], but I don't know how the prof. got this.
\[9-x ^{2}\ge0\] \[-x ^{2}\ge-9\] \[x ^{2}\le9\] \[x \le3\]
u understand what i did?
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im almost positive thats the answer but i havent looked at this material in a long time
Yes I do understand. Thank you very much.
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