Question

@agdgdgdo i proved ur answer please check it

Answer 1

\[x^2-y^2=(x+y)(x-y)\]
\[(x+y)^2=x^2+y^2+2xy\]
\[(x+y)^2-y^2-2xy=x^2\]
now put the value of x^2 in the identity
\[(x+y)^2-y^2-2xy-y^2=(x+y)(x-y)\]
\[(x+y)^2-2y^2-2xy=(x+y)(x-y)\]
\[(x+y)^2-2y(x+y)=(x+y)(x-y)\]
\[(x+y)(x+y-2y)=(x+y)(x-y)\]
\[(x+y)(x-y)=(x+y)(x-y)\] PROVED yuppi !!!!!!!!!!!!!!