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Use substitution to solve the system. (If the system is dependent, use the parameters y and z as necessary. If the system is inconsistent, enter INCONSISTENT.) 2 1 -- y+ -- z = -1 3 5 1 2 -- y - -- z =7 3 5 (y,z) = ( , )
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you didn't use my method
Multiply both equations by 15 and see what happens
Shannon, you there?
yeah, so times 2/3 by 15 and 1/5 by 15?
multiplying both by 15 should eliminate the denominators if you know how to do it
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so 2y + 1z =-1?
No, it's not that simple
You have to actually multiply each term by 15 then cancel and reduce: |dw:1318042023258:dw|
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