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change f(x) = 30(0.94)^x to an exponential function with base e.
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General form of exponential function is \[y= A e^{kx}\]
Which, by index laws can be expressed as
\[y=A[e^{k}]^{x}\]
remember when you raise one power to another power, you multiply the powers.
Now it's just a matter of matching terms.
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A=30 (obviously)
e^(k) = 0.94 ---> k = ln(0.94) = -0.06188 (to 5dp)
So, \[y= 30e^{-0.06188x}\]
thank you so much! makes perfect sense
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