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divide and simplify (7x-28)/33 / (x-4)/22x
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\[\frac{7(x-4)}{33} \times \frac{22x}{x-4}\]
i got as far as 154x^2-616x / 3x-12 but not sure if it is right or where to go from there
\[\frac{7\cancel{(x-4)}}{33} \times \frac{22x}{\cancel{x-4}}\]
ahhhh, ok saifoo, thank you
No problem, now cancel out 22/33 = 2/3 So finally you are left with: 7*2x ---- 3
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14x ---- 3 Answer
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