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How do you factor 2y^2-3y-35?
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(y-5)(2y+7)
can you explain how you did that please?
?
2y^2-10y+7y-35=0 2y(y-5)+7(y-5) (2y+7)(y-5)
-10y and 7y multiply to give -70y^2 and add to give -3y
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