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Mathematics 11 Online
OpenStudy (anonymous):

How do you factor 2y^2-3y-35?

OpenStudy (mimi_x3):

(y-5)(2y+7)

OpenStudy (anonymous):

can you explain how you did that please?

OpenStudy (anonymous):

?

OpenStudy (anonymous):

2y^2-10y+7y-35=0 2y(y-5)+7(y-5) (2y+7)(y-5)

OpenStudy (anonymous):

-10y and 7y multiply to give -70y^2 and add to give -3y

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