Question

Can you show me how to solve this example?

3x^2+8=0

Answer 1

\[3x^2=-8\]
if you are working with real numbers you are done, because a square cannot be negative.
if you are working with complex numbers then
\[x^2=\frac{-8}{3}\]
\[x=\pm\sqrt{-\frac{8}{3}}\]
\[x=\pm\sqrt{\frac{8}{3}}i\]