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how to get a perimeter a of a rectangle with a width of 8x^2y cm and 12x^2
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perimeter=2(8x^2y)+2(12x^2)=16x^2y+24x^2 with the information given this is the most you can do
good?
uh
:})
are u sure??
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my teacher wrote 40x^2cm
in your first term you have a y variable (look at your orignial question); if that is not here then you get the answer 40x^2
perimeter=2(8x^2)+2(12x^2)=16x^2+24x^2=40x^2
with out the other y 40x^ is the answer??
if the y is there the two terms are not "similar" or "like" and we can't add them together and make a single term
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ahh kk thnx
np :})
pls dont leave i have more questions ... sori
uh how to do this x^3.x^2=x^6 the solution pls.......
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