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Find the slope if it exists , of the line containing the pair of points (6,2) (10,-6)
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i ended up with - 4/8 is this right?
4/4=1
it should be -2.
ahh i didnt simplify
nono, it's the other way around, -8/4, not -4/8
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slope : deltay / deltax now choose (6,2) as point number one and (10,-6) as point number two (y1 - y2) / (x1-x2) (2-(-6)) / (6 - 10 ) = 8 / -4 = -2
i thought it was x2-x1/y2-y1..??
no, it's the other way around.
no no !!!
dy/dx
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so the answer is -8/4 ? not -4/8
which is -2.
okay
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