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how many positive factors of 540 are there
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540 contains 16 even and 8 odd positive factors
40=2^2 + 3^3 + 5^1 the number of all factors (divisors) for 540, 2+1=3, 3+1=4, 1+1=2 => 3*4*2=24 factors (divisors) note that there 2^2 primes, 2 is even => a number is even if it is divided by 2 => number of the evens is 2 times more e.g. for 1 odd there are 2 evens 24 factors=16 even+8 odd you can test this with many numbers say 12 /2 => 6 /2 => 3 /3 => 1 2^2 + 3^1 => (2+1)*(1+1)=6 factors => 2 evens for 1 odd 4 evens {2,4,6,12} and 2 odds {3,1} .............. number 270 has 16 factors <=> 2^1 + 3^3 + 5^1 => 2*4*2=16
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