Question

The sum of four consecutive even integers is 308. Write and solve an euation to find the four integers

Answer 1

Suppose the number be x.

Now,
First # = x
Second # = x+1
Third # = x + 2
Forth = x+3

Answer 2

Now,
x + (x+1) + (x+2) + (x+3) = 308

Answer 3

Solve for x.

Answer 4

Since the consecutive numbers are even, shouldn't it be:
x + x + 2 + x + 4 + x + 6 = 308

Answer 5

\[n+n+2+n+4+n+6=308\]
\[4n+12=308\]
\[4n=296\]etc