Question

Soybean meal is 12% protein ; cornmeal is 6%. How many pounds of each should be mixed together in order to get 240-Ib mixture that is 9% protein ?
How many pounds of the corn meal should be in the mixture ? _____ pounds
How many pounds of the soybean meal should be in the mixture ______ pounds

Answer 1

cornmeal: 120lb

soyabean: 120lb

Answer 2

saifoo you sure

Answer 3

Yes, 101%. ^_^

Answer 4

Let me show you.

Answer 5

Since 9% is halfway between 12% and 6%, it would need 120 lb of each

However, here is the algebra procedure:

Let x = amt of soybean meal (12%)

It says the resulting amt = 240 lb, therefore:
(240-x) = amt of cornmeal (6%)

write the decimal equiv of the per cent protein equation:
0.12x + 0.06(240-x) = 0.09(240)

0.12x + 14.4 - 0.06x = 21.6

0.12x - 0.06x = 21.6 - 14.4

0.06x = 7.2

x = 7.2/0.06

x = 120.