Question

Find the direct variation equation which passes through (0, 0) and (4, 1).

Answer 1

m = (y2-y1)/(x2-x1)


m = (1-0)/(4-0)


m = 1/4


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y = mx+b


0 = (1/4)(0)+b


0 = 0+b


0 = b


b = 0


y = mx+b


y = (1/4)x+0


y = (1/4)x


Equation is \[\Large y = \frac{1}{4}x\]