Find the value of X. Round to the nearest hundredth.
9^(2x+3) = 568

Question

anonymous · Answer

real solution -0.06

anonymous · Answer

x=-0.056788076162439606408046041536045944

anonymous · Answer

Thanks, but i'm stuck in the work, i'm not sure how one would get there. Could you show the work for me please ;)?

anonymous · Answer

Ok you have $$9^{(2x+3)}=568$$
take the log of both sides to base 9, so you have

$$2x+3 = \log_9(568)\rightarrow \frac{\ln{568}}{\ln(9)}$$
subtract 3 from both sides to get
$$2x = \frac{\ln{568}-3\ln9}{\ln(9)} \Rightarrow x= \frac{\ln{568}-3\ln9}{2\ln(9)}$$
which is approximately the real solution $$x =-0.056788076162439606408046041536045$$

anonymous · Answer

$$\ln x$$ is the natural log of x