Question

Find the value of X. Round to the nearest hundredth.
9^(2x+3) = 568

Answer 1

real solution -0.06

Answer 2

x=-0.056788076162439606408046041536045944

Answer 3

Thanks, but i'm stuck in the work, i'm not sure how one would get there. Could you show the work for me please ;)?

Answer 4

Ok you have \[9^{(2x+3)}=568\]
take the log of both sides to base 9, so you have

\[2x+3 = \log_9(568)\rightarrow \frac{\ln{568}}{\ln(9)}\]
subtract 3 from both sides to get
\[2x = \frac{\ln{568}-3\ln9}{\ln(9)} \Rightarrow x= \frac{\ln{568}-3\ln9}{2\ln(9)}\]
which is approximately the real solution \[x =-0.056788076162439606408046041536045\]

Answer 5

\[\ln x\] is the natural log of x