Question

(m) varies directly as the square of (t). If (m) is 7 when (t) is 1, what is the value of (m) when t is 2.

Answer 1

7m=t
7*2m=t*2

Answer 2

2t=14m

Answer 3

Since t squared varies directly as m you multiply t squared by the constant k.
m=kt^2
Then, solve for k using the first information given.
7=k1^2
7=k
Afterward getting k, you can just plug in t to get the new m.
m=7*2
m=14

Answer 4

\[m(t)=kt^2\]
\[m(1)=k(1^2)=7\rightarrow k=7\]
\[m(2)=7(2)^2 = 28\]

Answer 5

oops, cyter's right I forgot to square 2