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Please help me with this quadratic equation question.
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"Find an equation with roots 2+3i and 2-3i"
x = 2+3i or x = 2-3i x = 2 +- 3i x-2 = 3i (x-2)^2 = 9i^2 (x-2)^2 = -9 (x-2)^2 +9 = 0 x^2-4x+4+9 = 0 x^2-4x+13=0
Thanks !! let me try to read it and understand now..but that's the right answer :D
... I think the answer is 1/2x^2-\[\sqrt{2}\]x+5/2
xD are you sure that's the answer to this questiON
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in this question, you should know ax^2+bx+c and \[x= -b+-\sqrt{b^2-4ac}/2a\] and you can calculate it.
err okay ill give you a medal anyways for your time (:
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