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Mathematics 16 Online
OpenStudy (anonymous):

TWO PLANES ARE 1500 MILES APART AND TRAVELING TOWARD EACHOTHER. ONE PLANE IS TRAVELING 100MPH FASTER THAN THE OTHER PLANE. THEY MEET IN 1.5 HRS. FIND THE SPEED AT EACH PLANE? ( SHOW STEPS PLZ)

OpenStudy (anonymous):

r t = d Let x be the speed of the slower plane. Solve the following for x. (x + 100)*1.5 + x *1.5 =1500 x = 450 mph, x + 100 = 550 mph

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