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Mathematics 17 Online
OpenStudy (anonymous):

Limit x->1 [sin (x-1) / (x^2 +x-2)]

OpenStudy (anonymous):

You get 0/0. Therefore you can use lehospitals rule or however you spell it. The new equation is Cos(x-1) / 2x + 1 Now plug in x=1 and you get 1/3

OpenStudy (anonymous):

tahnks...can u help me w/ another limit prob?

OpenStudy (anonymous):

Give me good answer then post a new question ;-)

OpenStudy (anonymous):

ok

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