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Mathematics 25 Online
OpenStudy (anonymous):

(cosh^2(3t))-(sinh^2(3t))

OpenStudy (anonymous):

1

OpenStudy (anonymous):

The question used hyperbolic cosine and sine functions.

OpenStudy (kira_yamato):

Jm... In my opinion, I think Weeku-san is correct... Because these are hyperbolic functions and not the normal trigo function. So cosh^2 x + sinh^2 x = cosh2x cosh^2 x - sinh^2 x = 1

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