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Solve 4x^2 = 12x + 40.
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I solved it, and i'm not sure if it's right or not.. I got x = -2 and x = -5
x^2 - 3x - 10 = 0 => (x-5)(x+2) = 0 => x = 5 and x = -2
\[ 4x^{2} - 12x - 40 = 0 \] \[x^{2} - 3x - 10 = 0 \] Then Factor \[(x-5)(x+2) = 0\] So x = -2 and +5, you got it.
Thank you! (:
ur welcome
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