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Linear algebra Question
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post it please
det(A−λI)=0
where A= 1 -2 3 -4
I have a question for you (Turning Test) its on my page
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Eigenvalues? \[A-\lambda I=\] 1-lambda -2 3 -4-lambda I'm just going to put an x for lambda because it is easier so the determinant is (1-x)(-4-x)-(3)(-2)=-4-5x+x^2+6=x^2-5x+2 solve for x (really lambda)
Sorry I distributed wrong: (1-x)(-4-x)-(3)(-2)=-4+3x+x^2+6=x^2+3x+2=0 solve for x (really lambda)
|dw:1318268961548:dw| =(1-x)(-4-x)-(3)(-2)
ohhh,,, yea... i was doing it like that but it looked weird,,,
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