The sides of a triangle have measures of x, x, and y, and the perimeter of the triangle is 46. The measure y is 4 centimeters longer than the measure x. Write two equations which represent the two sentences.

Solve the system you wrote for this using any technique.

Question

The sides of a triangle have measures of x, x, and y, and the perimeter of the triangle is 46. The measure y is 4 centimeters longer than the measure x. Write two equations which represent the two sentences.

Solve the system you wrote for this using any technique.

anonymous · Answer

2x + y = 46
y = x + 4
subtract:
2x = -x + 42
3x = 42
x = 14
y = 14+4 = 18

sides of the triangle are 14,14 and 18