Question

(x+8)(x−2)2 > 0
How do I graph this? I'm pretty sure I'm doing it right, but my online hw website is telling me I'm wrong.

Answer 1

How are you doing it?

Answer 2

x+8>0, so I subtract 8, so I get x>-8 for the first one

Answer 3

for the second, (x-2)(x-2)>0, so i get x^2-4x+4>0, then i subtract 4 from both sides, after that i divide by -4, finally i square root to get x>1