Question

4-x^2>or=0
How do I graph this on a number line?

Answer 1

first you have to solve the inequality. you have
\[4-x^2\geq 0\]
\[(2-x)(2+x)\geq 0\] so the solution is
\[-2\leq x\leq 2\]

Answer 2

I'm not sure how factoring helps.\[4-x^{2}\ge0\]\[x^{2}\le4\]\[-2 \le x \le 2\]