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OpenStudy (anonymous):
How do i find the axis of symmetry of y–2=2(x +1)^2?
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OpenStudy (saifoo.khan):
y–2=2(x +1)^2? y = 2(x+1) + 2 solve the inner parenthesis for x. (x+1) = 0 x = 1 <--- axis of symmetry.
OpenStudy (anonymous):
where did the ^2 go?
OpenStudy (saifoo.khan):
that remains there. it is not needed here.
OpenStudy (anonymous):
okay so woulndt it be x= -1?
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