Question

y varies jointly with p and q. When p = 2 and q = 3, y = 48. Find y when p = 3 and q = 4.

Answer 1

\[y = kpq.\]

Answer 2

\[48 = k (2)(3)\]\[k = \frac{48}{6}\]\[k=8\]

Answer 3

So, final equation will be,

\[y = 8pq\]

Insert the values and solve.