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x^2=14x-49
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x^2-14x+49 =0
x = 7
x^2-7x-7x+49 = 0 x(x-7)-7(x-7) = 0 (x-7)(x-7) = 0 (x-7)^2 = 0 x - 7 = 0 x = 7
\[(x ^{2} - 7x - 7x) =0 ?\]
No
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I posted the steps above
why do you still use the 49 ?
What happens if you split the middle term? 14x becomes -7x - 7x
oooh . okaay
Then you can factor by grouping
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