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Use the function defined below to find an equation of the tangent line at the point indicated. y = cos(x), x = pi/3
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Please show steps.
take the derivative, get \[-\sin(x)\] then find \[-\sin(\frac{\pi}{3})\] for your slope.
then use the point - slope formula to find the equation for the line.
Would I write it as -sin(pi/3) or would I make it -(sqrt(3)/2)?
you need the second one, the actual number
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Alright. Thank you!
yw
Could you help me finish the equation? :p
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