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log 2^x = 3please
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Which one is it \[(\log2)^{x}=3\] or \[\log (2^{x})=3\]
the second one log ()
k use the log identity that says: \[\log(a^{x})\rightarrow xlog(a)\] in your case a=2 so: \[\log(2^{x})=3\rightarrow xlog(2)=3\] then solve for x: \[x=\frac{3}{\log(2)}\]
so would it be 8 or 9? becuase i feel like 5 or 6 would be off a bit ? what you think?
the answer is approximately 9.966 \[x \approx9.966\]
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